4x+3x^2=95

Solution for 4x+3x^2=95 equation:

4x+3x^2=95

We move all terms to the left:

4x+3x^2-(95)=0

a = 3; b = 4; c = -95;
Δ = b2-4ac
Δ = 42-4·3·(-95)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-34}{2*3}=\frac{-38}{6}
=-6+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+34}{2*3}=\frac{30}{6}
=5
$